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x=1.6x-1.6x^2
We move all terms to the left:
x-(1.6x-1.6x^2)=0
We get rid of parentheses
1.6x^2-1.6x+x=0
We add all the numbers together, and all the variables
1.6x^2-0.6x=0
a = 1.6; b = -0.6; c = 0;
Δ = b2-4ac
Δ = -0.62-4·1.6·0
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.6)-\sqrt{0.36}}{2*1.6}=\frac{0.6-\sqrt{0.36}}{3.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.6)+\sqrt{0.36}}{2*1.6}=\frac{0.6+\sqrt{0.36}}{3.2} $
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